0=-0.03x^2+1.3x+16

Solution for 0=-0.03x^2+1.3x+16 equation:

0=-0.03x^2+1.3x+16

We move all terms to the left:

0-(-0.03x^2+1.3x+16)=0

We add all the numbers together, and all the variables

-(-0.03x^2+1.3x+16)=0

We get rid of parentheses

0.03x^2-1.3x-16=0

a = 0.03; b = -1.3; c = -16;
Δ = b2-4ac
Δ = -1.32-4·0.03·(-16)
Δ = 3.61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.3)-\sqrt{3.61}}{2*0.03}=\frac{1.3-\sqrt{3.61}}{0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.3)+\sqrt{3.61}}{2*0.03}=\frac{1.3+\sqrt{3.61}}{0.06}
$